6a^2+a-5=0

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Solution for 6a^2+a-5=0 equation: 



6a^2+a-5=0

a = 6; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·6·(-5)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$


$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-11}{2*6}=\frac{-12}{12}
=-1
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+11}{2*6}=\frac{10}{12}
=5/6
$

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